deryaven
Vs=300ml=0,3 l
Cm=1,5 M => 0,45 moli de acid acetic ( Vs x Cm)
2CH3-COOH + Zn--> (CH3COO)2ZN + H2
La 2 moli acid acetic....1 mol Zn
la 0,45.......x moli Zn
x=0,225 moli de Zn
masa moleculara Zn = 65 g/mol
=> m=14,625 g Zn pur
P= m purx 100/m impur= 14,625x 100/15 = 97,5%